Master Chapter 3.3 of SEBA Class 9 Mathematics (Coordinate Geometry) with detailed step-by-step solutions, key formulas, and tips designed to help you score 100% in your Assam Board exams.

📘 Quick Summary & Chapter Info:

• Board: SEBA (Board of Secondary Education, Assam)
• Class: Class 9
• Subject: Mathematics
• Chapter: Chapter 3 – Coordinate Geometry (স্থানাংক জ্যামিতি)
• Exercise: 3.3 Solutions
• Medium: English & Assamese Medium

SEBA Class 9 Exercise 3.3 Latest Sylabus 2026-27

Question. 1

In which quadrant or on which axis do each of the points (-2, 4), (3, -1), (-1, 0), (1, 2) and (-3, -5) lie? Verify your answer by locating them on the Cartesian plane.

Answer:-

(-2, 4) lies in IInd Quadrant

(3, -1) lies in IVth Quadrant

(-1, 0) lies on negative x-axis

(1, 2) lies in Ist Quadrant

(-3, -5) lies in IIIrd Quadrant

Question. 2

Plot the points (x, y) given in the following table on the plane, choosing suitable units of distance on the axes.

x	-2	-1	0	1	3
y	8	7	-1.25	3	-1

Answer:-2

Question 3.

In the following question there is a statement of assertion (A) is followed by a statement of reason (R). Choose the correct option from given alternatives.

Assertion (A) : The coordinates of any point in the 3rd quadrant are (-x, -y), x > 0, y > 0.

Reason (R) : In the 3rd quadrant both x and y coordinates are negative.

(a) Both assertion (A) and reason (R) are true and reason (R) is correct explanation of assertion (A).

(b) Both assertion (A) and reason (R) are true but reason (R) is not correct explanation of assertion (A).

(c) Assertion (A) is true, but reason (R) is false.

(d) Assertion (A) is false, but reason (R) is true.

Answer 3 :-

(a) Both assertion (A) and reason (R) are true and reason (R) is correct explanation of assertion (A).

Question 4.

Match the statements of column (A) with column (B) and then choose the correct option.

Column (A)	Column (B)
1. (6, 0)	(i) Negative x-axis
2. (0, -6)	(ii) Positive x-axis
3. (-10, 0)	(iii) 4th quadrant
4. (3, -4)	(iv) Negative y-axis

(a) 1 -> (ii), 2 -> (iv), 3 -> (i), 4 -> (iii)

(b) 1 -> (iv), 2 -> (ii), 3 -> (i), 4 -> (iii)

(c) 1 -> (ii), 2 -> (iv), 3 -> (iii), 4 -> (i)

(d) 1 -> (ii), 2 -> (i), 3 -> (iv), 4 -> (iii)

Answer 4 :-

1 -> (ii), 2 -> (iv), 3 -> (i), 4 -> (iii)

Question 5.

A rectangle is formed on the coordinate plane with vertices at (0, 0), (4, 0), (4, 3) and (0, 3). The length of the diagonals is :

(a) 9 Units

(b) 7 Units

(c) 5 Units

(d) 4 Units

Answer 5 :-

(c) 5 Units

Question 6.

If we arrange the following points in ascending order of their distances from the origin then which of the given options represents the correct order :

A (3, 4), B(0, 6), C(6, 8)

(a) C B A

(b) C A B

(c) A C B

(d) A B C

Answer 6 :-

(d) A B C

Question 7.

The vertices of a triangle are (-3, 0), (3, 0) and (3, 6). Verify that the hypotenuse of the right triangle is 6√2.

Answer 7 :-

Let the given vertices be:

P(-3, 0)

Q(3, 0)

R(3, 6)

Calculating side lengths: PQ = √((3 – (-3))^2 + (0 – 0)^2) = √(6^2) = 6

QR = √((3 – 3)^2 + (6 – 0)^2) = √(6^2) = 6

PR = √((3 – (-3))^2 + (6 – 0)^2) = √(6^2 + 6^2) = √(36 + 36) = √72 = 6√2

Since PQ^2 + QR^2 = 6^2 + 6^2 = 36 + 36 = 72 = (6√2)^2 = PR^2, △PQR is a right-angled triangle.

Therefore, the hypotenuse is PR = 6√2. (Hence verified)

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