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char *ptr, x = ‘A’; ptr = &x; char y = ++(*ptr); printf(“\n %c”, y); Output:B Reasoning x is initialized to ‘A’ (ASCII 65) 🏷️ ptr stores the address of x → ptr = &x 🏷️ Expression ++(ptr): printf(“\n %c”, y); prints y, which is ‘B’ Final Output:B (because pre-increment updates x before assignment). Are…
char *ptr, x = ‘A’; ptr = &x; char y = (*ptr)++; printf(“\n %c”, y); Output:A Reasoning x is initialized to ‘A’ (ASCII 65) ptr stores the address of x → ptr = &x Expression (ptr)++: printf(“\n %c”, y); prints y, which is ‘A’ Final Output:A (because post-increment returns the original value first).But x is…
char *ptr, x = ‘A’; ptr = &x; char y = *ptr; printf(“\n %c”, y); Output:A Reasoning x is initialized to ‘A’ → x = ‘A’ ptr stores the address of x → ptr = &x char y = ptr; printf(“\n %c”, y); prints y, which is ‘A’ Final Output:A (because y stores the value…
int *ptr, x = 9; ptr = &x; int y = ++(*ptr); printf(“\n %d”, y); Output:10 Reasoning x is initialized to 9 → x = 9 ptr stores the address of x → ptr = &x y = ++(ptr); printf(“\n %d”, y); prints y, which is 10 Final Output:10 (because x was incremented before assignment…
int *ptr, x = 9; ptr = &x; printf(“\n %d”, (*ptr)++); printf(“\n %d”, *ptr); Output:910 Reason:- x is initialized to 9 → x = 9 ptr stores the address of x → ptr = &x First printf(“\n %d”, (ptr)++); Second printf(“\n %d”, ptr); Final Output:9 (before increment)10 (after increment) Are you looking for the Class…
int *ptr, x = 9; ptr = &x; printf(“\n %d”, (*ptr)++); Output:9 Reason:-In the above program. x is initialized to 9 ptr stores the address of x (*ptr)++ means:*ptr (value at address ptr) is 9 Final Output:9 (because post-increment prints the original value first). Are you looking for the Class 10 Computer Science SEBA Solution?…
An int pointer requires 4 bytes of memory to store. Similarly, a char pointer also needs 4 bytes of memory. Are you looking for the Class 10 Computer Science SEBA Solution? You are in the right place! This guide provides accurate, well-structured, and easy-to-understand solutions to all topics covered in the SEBA Class 10 Computer…
Dynamic memory allocation allows you to reuse memory and free it when it’s no longer needed, making it more efficient. Unlike static memory allocation, it may run slower, but it allows you to release memory at any point during the program. This makes dynamic memory allocation a powerful way to manage memory efficiently. Are you…
A pointer is a type of variable that, instead of storing a regular value like an integer, a double, or a character, stores the memory address of another variable. Just like normal variables, pointers need to be declared before using Are you looking for the Class 10 Computer Science SEBA Solution? You are in the…
`#include<stdio.h>#include<string.h> int main(){char Your_name[20],Mother_name[20]; } Example Output:“`Enter your name: Asgar Enter your mother name: Hamida Your name is: Asgar Your mother name is: Hamida Are you looking for the Class 10 Computer Science SEBA Solution? You are in the right place! This guide provides accurate, well-structured, and easy-to-understand solutions to all topics covered in the…