Path To Success
4 3 2 14 3 2 14 3 2 14 3 2 14 3 2 1 #include<stdio.h>int main(){ for(int i=1;i<=5;i++) { for(int j=4;j>=1;j–){printf(“%d”,j);} printf(“\n”); } return 0;} Are you looking for the Class 10 Computer Science SEBA Solution? You are in the right place! This guide provides accurate, well-structured, and easy-to-understand solutions to all topics…
1 2 11 2 11 2 11 2 11 2 1 #include<stdio.h>int main(){ } return 0;} Are you looking for the Class 10 Computer Science SEBA Solution? You are in the right place! This guide provides accurate, well-structured, and easy-to-understand solutions to all topics covered in the SEBA Class 10 Computer Science syllabus. Our Class…
1 2 31 2 31 2 31 2 31 2 3 #include<stdio.h>int main(){ return 0;} Are you looking for the Class 10 Computer Science SEBA Solution? You are in the right place! This guide provides accurate, well-structured, and easy-to-understand solutions to all topics covered in the SEBA Class 10 Computer Science syllabus. Our Class 10…
To draw the pattern 5 4 3 2 1 5 4 3 2 5 4 3 5 4 5 Without using Nested Loop #include<stdio.h>int main(){ for(int i=5;i>=1;i–)printf(“%d”,i);printf(“\n”);for(int i=5;i>=2;i–)printf(“%d”,i);printf(“\n”);for(int i=5;i>=3;i–)printf(“%d”,i);printf(“\n”);for(int i=5;i>=4;i–)printf(“%d”,i);printf(“\n”);for(int i=5;i>=5;i–)printf(“%d”,i);printf(“\n”);printf(“\n”);printf(“\n”);printf(“\n”);printf(“\n”); return 0;} Using Nested Loop #include<stdio.h>int main(){ for(int i=1;i<=5;i++) { for(int j=5;j>=i;j–){printf(“%d”,j);}printf(“\n”); } return 0;} Are you looking for the Class 10 Computer Science…
To draw the pattern 55 45 4 35 4 3 25 4 3 2 1 Without using Nested Loop #include<stdio.h>int main(){ for(int i=5;i>=5;i–)printf(“%d”,i);printf(“\n”);for(int i=5;i>=4;i–)printf(“%d”,i);printf(“\n”);for(int i=5;i>=3;i–)printf(“%d”,i);printf(“\n”);for(int i=5;i>=2;i–)printf(“%d”,i);printf(“\n”);for(int i=5;i>=1;i–)printf(“%d”,i);printf(“\n”);printf(“\n”);printf(“\n”);printf(“\n”);printf(“\n”); return 0;} Using Nested Loop #include<stdio.h>int main(){ for(int i=5;i>=1;i–){for(int j=5;j>=i;j–){printf(“%d”,j);}printf(“\n”); } return 0;} Are you looking for the Class 10 Computer Science SEBA Solution? You are in the…
To draw the pattern 11 11 1 11 1 1 11 1 1 1 1 Without using Nested Loop #include<stdio.h>int main(){ for(int i=1;i<=1;i++)printf(“1”);printf(“\n”);for(int i=1;i<=2;i++)printf(“1”);printf(“\n”);for(int i=1;i<=3;i++)printf(“1”);printf(“\n”);for(int i=1;i<=4;i++)printf(“1”);printf(“\n”);for(int i=1;i<=5;i++)printf(“1”);printf(“\n”);printf(“\n”);printf(“\n”);printf(“\n”);printf(“\n”); return 0;} Using Nested Loop #include<stdio.h>int main(){ for(int i=1;i<=5;i++){for(int j=1;j<=i;j++){printf(“1”);}printf(“\n”); } return 0;} Are you looking for the Class 10 Computer Science SEBA Solution? You are in the…
#include<stdio.h> int main() {int a;char i; Sample Output: Enter a number: 5The number 5 is odd.Do you want to check another number? (y/n): yEnter a number: 10The number 10 is even.Do you want to check another number? (y/n): nProgram terminated. Programming #Coding #LearnToCode #CProgramming #CodeNewbie #ProgrammingTutorial #CodeChallenge #OddOrEven #DoWhileLoop #InputValidation #CodingPractice #BeginnerProgrammer #LogicBuilding #CodingFun #Developers…
#include <stdio.h> int main() { int N, sum = 0; printf(“Enter a positive integer N: “); scanf(“%d”, &N); for (int i = 1; i <= N; i++) { a= i * (i + 1); sum=sum+a; } printf(“The sum of products is: %d\n”, sum); return 0; } Output: Enter a positive integer N: 5 The…
#include <stdio.h> int main() { int i, N, sum = 0; printf(“Enter the value of N: “); scanf(“%d”, &N); for (i = 1; i <= N; i++) { int cube = i * i * i; sum = sum + cube; } printf(“\nThe summation of cubes is %d\n”, sum); return 0; } Output: Enter the…
#include<stdio.h>int main() {int N, a, sum = 0;printf(“Enter a positive integer N: “);scanf(“%d”, &N);for (int i = 1; i <= N; i++) {a= i * i;sum=sum+a;}printf(“The sum of squares from 1² to %d² is: %d\n”, N, sum);return 0;} Output:Enter a positive integer N: 5The sum of squares from 1² to 5² is: 55 Are you…